If p, q are zeroes of polynomial f(x) =2x^2-7x+3,find the value of p^2+q^2

Question

asked May 26, 2020 184k views

1 Answer

Tezromania · Answer 1 · 2020-06-02T02:17:52+0000

Answer:

p^2 + q^2 = 22/9.

Explanation:

For a quadratic function ax^2 + bx + c if the zeroes are A and B then

A + B = -b/a and AB = c/a.

2x^2 - 7x + 3

Now p and q are the zeroes of the above function so

p + q = 7/3 and pq = 3/2.

Now p^2 + q^2 = (p + q)^2 - 2pq

= (7/3)^2 - 2* 3/2

= 49/9 - 3

= 49/4 - 27/9

= 22/9.