Question

Factor this expression. x2 + 9x + 8 A. (x - 4)(x + 2) B. (x - 4)(x - 2) C. (x + 8)(x - 1) D. (x + 8)(x + 1)

Answer 1

D

Explanation:

Answer 2

Option D

Answer:

The factors of
`x^(2) + 9 x + 8` is (x + 8)(x +1)

Solution:

From question, given that
`x^(2) + 9x + 8`

To factorise the given equation, follow the below steps:

9x can be rewritten as 8x + 1x. Hence the above given equation becomes,

`x^(2) + 9x + 8 = x^(2) + 8x + 1x + 8`

Rearranging the terms, we get

`= x^(2) + 1x + 8x + 8`

Taking x as common from first two terms and 8 as common from last two terms, the above equation becomes,

= x(x+1)+8(x+1)

Since (x +1) is common in both the terms, we get

= (x +1)(x+8)

Hence the factors of
`x^(2) + 9x + 8` is (x + 8)(x +1)