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the sum of three consecutive numbers is one hundred twenty . what is the smallest of the three numbers ?

User Droptop
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1 Answer

7 votes

Answer:

The answer to your question is 39

Explanation:

Three consecutive numbers is 120

The smallest is = ?

The smallest will be n

The next one will be = n + 1

The highest will be = n + 2

Now, we add them

n + n + 1 + n + 2 = 120 Simplify like terms

3n + 3 = 120

3n = 120 - 3

3n = 117

n = 117 / 3

n = 39

n + 1 = 40

n + 2 = 41

39 + 40 + 41 = 120

User Atbebtg
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