Question

Which expression and value of six less than the quotient of a number and two increased by ten when n=8

Answer 1

Expression would be
`(n)/(2)-6+10`

Value would be 8.

Explanation:

Here, n represents the unknown number,

∵ The quotient of n and 2 =
`(n)/(2)`

6 less than
`(n)/(2)` =
`(n)/(2)-6`

`(n)/(2)-6` increased by 10 =
`(n)/(2)-6+10`

Thus, the required expression would be,

`(n)/(2)-6+10`

When n = 8,

`(8)/(2)-6+10=4-6+10=8`

Answer 2

The expression is
`(n)/(2)-6+10`

For n=8 the value of the expression is 8

Explanation:

Let

n -----> the number

we know that

"six less than" means we're subtracting 6:

- 6

"The quotient" means division. "Of a number and 2" Usually the numerator is listed first:

n/2

"increased by ten" means we're adding 10:

+10

substitute

`(n)/(2)-6+10`

For n=8

substitute the value of n in the expression

`(8)/(2)-6+10`

`4-6+10=8`