Question

High-speed stroboscopic photographs show that the head of a 160-g golf club is traveling at 43 m/s just before it strikes a 46-g golf ball at rest on a tee. After the collision, the club head travels (in the same direction) at 31 m/s. Find the speed of the golf ball just after impact.

Answer 1

Vb = 41.74m/s

Step-by-step explanation:

Let Voc be the velocity of the club before the collision, Vfc the velocity of the club after the collision, Vfb the velocity of the ball after the collision.

The masses of the club and the ball expressed in kg are:

mc = 0.16kg mb = 0.046kg

By conservation of the moment:

Po = Pf

mc*Voc + mb *0 = mc*Vfc + mb*Vfb Solving for Vfb:

`Vfb = (mc)/(mb)*(Voc - Vfc) = 41.74m/s`