Answer:21.45 m/s
Step-by-step explanation:
Given
Mass of sport car=920 kg
Mass of SUV=2300 kg
distance to which both car skid is 2.4 m
coefficient of friction (
)=0.8
Let u be the initial velocity of both car at the starting of skidding
and they finally come to zero velocity
![v^2-u^2=2as](https://img.qammunity.org/2020/formulas/physics/middle-school/kzr98dbu2wfj2ipzjwf8lasb185fsfra2y.png)
![acceleration=\mu g=0.8* 9.8=7.84 m/s^2](https://img.qammunity.org/2020/formulas/physics/high-school/6djc77b42dy4whhu9bup17gsqfgjmorpm0.png)
s=2.4 m
![0-(u)^2=2* (-7.84)* 2.4](https://img.qammunity.org/2020/formulas/physics/high-school/24wx7ng5p6jbmmwmg1rl9q0l5k6aed4kox.png)
u=6.13 m/s
so before colliding sport car must be travelling at a speed of
(conserving momentum)
v=21.45 m/s