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point A has coordinates (-5, 3). If point (1, 6) is 3/4 of the way from A to B, what are the coordinates of point B​

User Qorbani
by
5.9k points

2 Answers

3 votes

Answer:

The coordinates are 3,7 :)

Try thinking about partitioning a line segment

User Joey Ezekiel
by
5.9k points
4 votes

Answer:

The coordinates of point B are (3 , 7)

Explanation:

* Lets explain how to solve the problem

- If point (x , y) divides a line segments whose endpoints are
(x_(1),y_(1))

and
(x_(2),y_(2)) at ratio
(m_(1):m_(2)) from the first point
(x_(1),y_(1)), then


x=(x_(1)m_(2)+x_(2)m_(1))/(m_(1)+m_(2)) and


y=(y_(1)m_(2)+y_(2)m_(1))/(m_(1)+m_(2))

∵ Point A = (-5 , 3)

∵ The point of dinision (x , y) = (1 , 6)

∵ Point B =
(x_(2),y_(2))

- Point (1, 6) is 3/4 of the way from A to B, that means the distances

from A to (1 , 6) is 3 parts and from (1 , 6) to B is (4 - 3) = 1 part


(m_(1):m_(2)) = 3 : 1


1=((-5)(1)+x_(2)(3))/(3+1)


1=(-5+3x_(2))/(4)

- Multiply each side by 4


4=-5+3x_(2)

- Add 5 to both sides


9=3x_(2)

- Divide both sides by 3


x_(2)=3

The x-coordinate ob point B is 3


6=((3)(1)+y_(2)(3))/(3+1)


6=(3+3y_(2))/(4)

- Multiply each side by 4


24=3+3y_(2)

- Subtract 3 to both sides


21=3y_(2)

- Divide both sides by 3


y_(2)=7

The y-coordinate ob point B is 7

* The coordinates of point B are (3 , 7)

User Carloshwa
by
5.2k points