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Lucia has 3.5 hours left in her workday as a car mechanic. Lucia needs 1/2 of an hour to complete one oil change.

a. How many oil changes can Lucia complete during the rest of her workday?
b. Lucia can complete two car inspections in the same amount of time it takes her to complete one oil change. How long does it take her to complete one car inspection?
c. How many inspections can she complete in the rest of her workday?

2 Answers

2 votes

Answer:

a. 7 oil changes

b. 15 minutes (1/4 hour)

c. 14 inspections

Explanation:

a. Fist, we need to know that .5 of an hour is 1/2 an hour.

Then divide the 3.5 hours by how longs it takes to complete one oil change.

3.5/.5= 7 oil changes

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b. 2 inspections=same amount of time for an oil change

If it takes 1/2 an hour to complete the oil change and you can do 2 inspection in that time, divide 1/2 an hour by 2.

1/2 hour / 2 = 15 per inspection

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c. So now that we know EACH inspection takes 15 minutes, we just need to divide the amount of time she has left by the amount of time it takes to do an inspection.

3.5 hours / 15 minutes = 14 inspections

User Sofahamster
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7 votes

Answer: So LucĂ­a has 3.5 hours left, and need 1/2 of an hour (or 0.5 hours) to do one oil change.

a) If you divide the total time she has by the time she needs for each oil change, then you got the total number of oil changes that she can do in that time; this is:

3.5/0.5 = 7

So she can do 7 oil changes in 3.5 hours.

b) If she can complete two car inspections in the same amount of time it takes her to complete one oil change, then she can do two car inspections in 0.5 hours.

2*car inspections = 0.5 hours

car inspection = (0.5/2) hours

then one car inspection will take 0.5/2 = 0.25 hours.

c) Two ways to solve this:

1) Do the same that we did in a), this is: 3.5/0.25 = 14

she can do 14 car inspections.

2) If in 3.5 hours, she can do 7 oil changes, and in the time she does an oil change, she can do two car inspections, then in 3.5 hours she can do 7*2 car inspections, and 7*2 = 14

User Attacomsian
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