Question

After just 4 tenths of a 2.5-mile race was completed, Lenox took the lead and remained there until the end of the race.

a. How many miles did Lenox lead the race?
b. Reid, the second-place finisher, developed a cramp with 3 tenths of the race remaining. How many miles did Reid run without a cramp?

Answer 1

Lenox lead the race is = 1.5 miles

Reid run without a cramp = 1.75 miles

Explanation:

given data

Lenox lead race =
`(4)/(10)`

total race = 2.5 mile =
`(25)/(10)`

cramp =
`(3)/(10)`

to find out

How many miles did Lenox lead the race and How many miles did Reid run without a cramp

solution

we know Lenox lead =
`(4)/(10)` and total race is 2.5 mile

so

Lenox lead the race is =
`(4)/(10)` of 2.5 mile

Lenox lead the race is =
`(4)/(10)` ×
`(25)/(10)`

Lenox lead the race is =
`(15)/(10)` = 1.5 miles

and

we know developed a cramp with
`(3)/(10)` of the race remaining

so

without cramp race is 1 -
`(3)/(10)` =
`(7)/(10)`

and run without cramp is
`(7)/(10)` of 2.5 mile

Reid run without a cramp =
`(7)/(10)` ×
`(25)/(10)`

Reid run without a cramp =
`(175)/(100)`

Reid run without a cramp = 1.75 miles