Question

Farmer Dave harvested his corn. He stored 5/9 of his corn in one large silo and 3/4 of the remaining corn in a small silo. The rest was taken to market to be sold.

a. What fraction of the corn was stored in the small silo?
b. If he harvested 18 tons of corn, how many tons did he take to market?

Answer 1

Answer with Step-by-step explanation:

Part a)

Let the total corn be 'W'

Amount of corn stored in silo
`W_(silo)=(5)/(9)W`

Amount of corn remaining =
`W_(rem)=W-(5W)/(9)=(4W)/(9)`

Thus amount of corn stored in small silo

`W'=(3)/(4)* (4W)/(9)=(W)/(3)`

Thus fraction of original corn stored in small silo = 1/3

Part b)

Amount of corn sold in market =
`W_(sold)=(4W)/(9)-(W)/(3)=(W)/(9)`

Thus the amount of corn taken to market equals
`18* (1)/(9)=2tonnes`

Answer 2

a. 1/3

b. 2 tons

Explanation:

let the total corn store be unity

now corn left after storing in large silo = 1-5/9= 4/9

now 3/4 of the remaining is stored in small silo = 3/4 of 4/9= 3/4×4/9= 1/3

therefore 1/3 of total corn was store in small silo

b. corn left for market = 4/9 -1/3 =
`(4-3)/(9)`= 1/9

so, the 18 tons its 1/9 was marketed which means = 18/9 = 2 tons