Answer:
Expression:
![(23*(1)/(3))-5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rdw1gfakfjttrhocaj3v2e92wifwgaumcn.png)
After evaluate:
![2(2)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b1mcc61kw7ohu91rax6y364iuazcbjl4ak.png)
Explanation:
Notice that the exercise says "
of 23". This is:
![23*(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/umlyjvc6sxxmgvk4ea7xf8pehqhbdqyfhm.png)
According to the exercise, you must "Subtract 5 from
of 23"; knowing this you can write the following expression:
![(23*(1)/(3))-5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rdw1gfakfjttrhocaj3v2e92wifwgaumcn.png)
In order to evaluate the expression, the first step you need to apply is to solve the multiplication inside the parentheses:
![((23*1)/(3))-5=(23)/(3)-5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7f7mfld35a8ol848g6703tpt1g39k2ds4z.png)
Now you need to solve the subtraction.
Since the denominator of
is 3 and the denominator of 5 is 1 (
), the Least Common Denominator (LCD) is 3. Then:
![=(23-15)/(3)=(8)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kwadr6vly4h7jte0s90d50s4kfx8o22p66.png)
Finally, you can convert this improper fraction to a mixed number. The steps are:
- Divide the numerator 8 by the denominator 3. You will get 2, with a remainder of 2.
- Use 2 as the whole number, and the remainder 2 as the numerator.
- The denominator does not change. It's 3.
Then, you get:
![2(2)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b1mcc61kw7ohu91rax6y364iuazcbjl4ak.png)