An object starts from rest at the origin (x0 = 0) and travels in a straight line with a constant acceleration (a = constant). Suppose the relation between the position (x) and t…

Question

asked Jun 3, 2020 145k views

1 Answer

Milad Faridnia · Answer 1 · 2020-06-07T01:01:17+0000

Answer:

$a=(6.8)\ m/s^2$

Step-by-step explanation:

Given that,

An object starts from rest at the origin (x₀ = 0) and travels in a straight line with a constant acceleration (a = constant).

The relation between the position (x) and time (t) is given by :

$x=(3.4t^2)\ m/s^2$

Let v is the velocity of the object.

v=(dx)/(dt)

v=(d(3.4t^2))/(dt)

$v=(6.8t)\ m/s$

Let a is the acceleration of the object. It is given by :

a=(dv)/(dt)

a=(d(6.8t))/(dt)

$a=(6.8)\ m/s^2$

So, the acceleration of the object is
$(6.8)\ m/s^2$ . Hence, this is the required solution.