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Suppose a simple random sample of size nequals=6464 is obtained from a population with mu equals 84μ=84 and sigma equals 16σ=16. ​(a) Describe the sampling distribution of x overbarx. ​(b) What is Upper P (x overbar greater than 87.6 )P x>87.6​? ​(c) What is Upper P (x overbar less than or equals 79.2 )P x≤79.2​? ​(d) What is Upper P (81.3 less than x overbar less than 87.6 )P 81.3

User Obscure
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Answer:

a.
\bar X is distributed
N(84;4)

b.
P(\bar X \geq 87.6) = 0.03593

c.
P(\bar X \leq 79.2) = 0.00820

d.
P(\79.2 \leq \bar X \leq 87.6) = 0.95587

Explanation:

a.

The central limit theorem states that, for large n, the sampling distribution of the sample mean is approximately normal with mean
\µ and variance
(\sigma^2)/(n), then, the sample mean is distributed as a normal random variable with means
\mu_(\bar X)=\mu=84 and variance
\sigma^2_(\bar X)=(\sigma^2)/(n)=(16^2)/(64)=4.

b.


P(\bar X \geq 87.6) = 0.03593

c.


P(\bar X \leq 79.2) = 0.00820

d.


P(\79.2 \leq \bar X \leq 87.6) = 0.95587

User Quentin Del
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