Answer:
The range of possible temperatures is the interval [80.5°,95.5°]
Explanation:
Let
x -----> possible temperatures for that day.
we know that
The absolute value inequality of the difference of the possible temperatures and the temperature at noon must be less than or equal to 7.5° F
so
![\left|x-88\right|\le7.5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sq41hfb14b1qv2f5kbud4bfh5ru4cwevnm.png)
Solve the absolute-value inequality
First case (positive case)
![+(x-88) \leq 7.5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jx7x5gk7kevvpmxzgce1y8mb0uqhmh6ftz.png)
Adds 88 both sides
![x \leq 7.5+88](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6ydfbx3xdqrwq0zxdht169dc1lijggmvwx.png)
![x \leq 95.5\°](https://img.qammunity.org/2020/formulas/mathematics/middle-school/18t0zsbczc54x4mn8duh9255gd6rsdum3x.png)
Second case (negative case)
![-(x-88) \leq 7.5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/c2cu4a0qh21u1q0gn0iuiwak3xf6jade18.png)
Multiply by -1 both sides
![(x-88) \geq -7.5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1jr3x1ma66ce60cwn80kc1dasznir0sxjt.png)
Adds 88 both sides
![x \geq -7.5+88](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w3penqi1loxjjtq2zpbslpcow94vgg36pj.png)
![x \geq 80.5\°](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ugxudhp1mtpllvytgcjstz4w3el8khxn2y.png)
therefore
The range of possible temperatures is the interval [80.5°,95.5°]