Radium has a half-life of 1,660 years.The number of years until only 1/16th of a sample remains is 6641 years.
Answer: 6641 years
Step-by-step explanation:
Given that the half-life of Radium is 1660 years. The number of years to be calculated when the sample of radium could just be remained of 1/16th of its part, which can be calculated by the following means,
Half life,
![T_(1 / 2)=1660 \text { years }](https://img.qammunity.org/2020/formulas/physics/middle-school/46094h4s75m1cfclqhe0p9w6biqxxowtn4.png)
![(N)/(N_(0))=(1)/(16)](https://img.qammunity.org/2020/formulas/physics/middle-school/axagv1g3qj9gii12k7j0yisw2tfj7thwr1.png)
t is the taken time, then,
![(N)/(N_(0))=e^(-\lambda t)](https://img.qammunity.org/2020/formulas/physics/middle-school/ksw6849fosmferxy6e28esocd8w2280huf.png)
![(N)/(N_(0))=e^(\lambda t)](https://img.qammunity.org/2020/formulas/physics/middle-school/w5yxc7ar9qp6ui991zpcepsejh1tcq15gz.png)
Taking ln on both sides, we get,
![\lambda t=\ln \left((N)/(N_(0))\right)](https://img.qammunity.org/2020/formulas/physics/middle-school/tpw93yagypo8c7lrzaj394zo0hplwcuxo6.png)
![t=(1)/(\lambda) \ln \left((N_(0))/(N)\right)](https://img.qammunity.org/2020/formulas/physics/middle-school/9yk030eyxr3b0i9t2golexvz579ebb4ggh.png)
![=(T_(1 / 2))/(0.693)\left(\ln \left((N_(0))/(N)\right)\right)](https://img.qammunity.org/2020/formulas/physics/middle-school/pu5gff5bwkfe3nfqke9464f5tavlcey1x4.png)
By substituting the given values,
![t = (1660)/(0.693)(\ln 16)](https://img.qammunity.org/2020/formulas/physics/middle-school/d1qowe0k0rv3rqqaeplnic0tdfe9xg3p4h.png)
Therefore, t = 6641 years