Question

N2 + 3H2 = 2NH3

for the equation in (2) above, you have 1000. g of N2 and 150.0 g of H2:

a. Identify the limiting reactant. _____________

b. Calculate the theoretical yield in grams of NH3. __________

c. Calculate the grams of excess reactant. __________
show work

Answer 1

The answer to your question is:

a) Hydrogen

b) 850 g of NH3

c) 300 g of N2

Step-by-step explanation:

N2 + 3H2 ⇒ 2NH3

N2 = 1000 g

H2 = 150 g

a. Identify the limiting reactant.

MW N2 = 28 g

MW H2 = 2 g

MW NH3 = 17g

N2 + 3H2 ⇒ 2NH3

28g ------ 3(2)

1000 g ------ x

x = (1000 x 6)/ 28

x = 214.3 g of H2

Then, the limiting reactant is H2, because is necessary to have 214.3 g of H2 to react with 1000 g of N2, and there are only 150 g.

b. Calculate the theoretical yield in grams of NH3. __________

N2 + 3H2 ⇒ 2NH3

6g -----------2(17)g

150g --------- x

x = (150 x 34) / 6

x = 850 g of NH3

c. Calculate the grams of excess reactant. __________

N2 + 3H2 ⇒ 2NH3

28g -------- 6 g

x ----------- 150 g

x = (150 x 28)/ 6

x = 700 g of N2

Excess reactant = 1000g - 700g

= 300 g of N2