Answer:
k=8
The problem:
The function y=2x+2 and y=-x+k intersect at the point (2,6).
Find the value of k.
Explanation:
(2,6) is a point contained by both y=2x+2 and y=-x+k.
Let's see if it actually on y=2x+2.
x=2,y=6
y=2x+2
6=2(2)+2
6=4+2
6=6 is true so it (2,6) is on y=2x+2.
Now we want k such that (2,6) is on y=-x+k.
6=-2+k
Add 2 on both sides:
8=k
So k=8.