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There are 5 Snickers, 10 Baby Ruths, 13 Milky Ways, 12 Twixs and17 Almond Joys in a bowl of candy. You reach into the bowl and randomly select 5 candy bars. Use this information to answer the next two questions. What is the probability you select exactly 2 Milky Way bars?

User Swenedo
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1 Answer

2 votes

Answer: 0.2415

Explanation:

Given : There are 5 Snickers, 10 Baby Ruths, 13 Milky Ways, 12 Twixs and17 Almond Joys in a bowl of candy.

Total candy bars :
5+10+13+12+17=57

Probability of getting a Milky Way bar=
p=\frac{\text{No. of Milky bars}}{\text{Total candy bars}}


\Rightarrrow\ p=(13)/(57)\approx0.23

Using Binomial distribution , the probability of getting success in x trials is given by:-


P(x)=^nC_xp^x(1-p)^(n-x), where p uis probability of success in each trial and n is sample size.

If you randomly select n= 5 candy bars, then the probability you select exactly 2 Milky Way bars Will be :_


P(2)=^5C_2(0.23)^2(1-0.23)^(3)\\\\=(5!)/(2!(5-2)!)(0.23)^2(0.77)^3\\\\=0.241505957\approx0.2415

Hence, the probability you select exactly 2 Milky Way bars = 0.2415

User RevMoon
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