Answer:
The solution you got is wrong; (2,1)
Explanation:
S (2,1) Eq= 3y - 4 - x = 3
Eq = y = mx + c
= 3y - 4 - x = 3
(Put your x and y value in if they equal to 3 then it the solution if it not equal to 3 then your answer is wrong)
-> 3(1) - 4 - 2 = 3
-> 3-4 -> -1 - 2 = 3
-> -3 = 3
- The solution you got is wrong; (2,1)