Question

According to Wien's Law, how many times hotter is an object whose blackbody emission spectrum peaks in the blue, at a wave length of 450 nm, than a object whose spectrum peaks in the red, at 700 nm? Please show me your calculations.

Answer 1

Answer:1.55 times

Step-by-step explanation:

Given

First wavelength
`(\lambda _1)=450 nm`

Second wavelength
`(\lambda _2)=700 nm`

According wien's diplacement law

`\lambda T=constant`

where
`\lambda =wavelength`

T=Temperature

Let
`T_1 and T_2` be the temperatures corresponding to
`\lambda _1 & \lambda _2` respectively.

`\lambda _1* T_1=\lambda _2* T_2`

`(T_1)/(T_2)=(\lambda _2)/(\lambda _1)`

`(T_1)/(T_2)=(700)/(450)=1.55`

Thus object with
`\lambda 450 nm` is 1.55 times hotter than object with wavelength
`\lambda =700 nm`