Question

A train leaves at 0836 and arrives at 1057. It travelled at an average speed of 85 km/h. How far did it travel?

Answer 1

Answer: it traveled a distance of 199.75Km

Explanation:

From the question , Let 0836 be 8:36

and 1057 be 10:57

Time of departure= 8:36

Time of arrival = 10:57

Time traveled = 10:57- 08:36= 2 Hours 21 minutes

changing trhe time to hours becomes 21/60 = 0.35 hours + 2 HOURS = 2.35 hours

Step 2

Speed = Distance / Time

Distance = Speed x Time

=85 km/hr x 2.35 hours

=199.75Km

Answer 2

199.75km

Explanation:

Step one:

given data

We are told that the time of travel is from

8:36- to 10:57

which is 2 hours 21 minutes

Hence the time taken is 2.35 hours

the speed is 85km/h

Step two:

From the expression

speed= distance/time

85= distance/2.35

distance= 85*2.35

distance= 199.75km