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You are playing frisbee golf and get a hole in one by throwing the disc 75.6 m. If the disc traveled at a constant speed of 12.5 m/s. How long did it take to hit the target

User Ashtom
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1 Answer

5 votes

Answer:

6.05 seconds

Step-by-step explanation:

we know that

The speed is the ratio between the distance and the time

Let

s -----> the speed in meters per second

d ----> the distance in meters

t ---> the time in seconds


s=(d)/(t)

In this problem we have


s=12.5\ (m)/(sec)


d=75.6\ m

substitute in the formula and solve for t


12.5=(75.6)/(t)

Multiply by t both sides


12.5t=75.6

Divide by 12.5 both sides


t=6.05\ sec

User AvgJoe
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