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I need help with 11 and 12

I need help with 11 and 12-example-1

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Answer:

Both are inverse pairs

Explanation:

Question 11


g(x)= 4 + (8)/(5)x

(a) Rename g(x) as y


y = 4 + (8)/(5)x

(b) Solve for x :


(8)/(5)x = y - 4

(c) Multiply each side by ⅝


x = (5)/(8)(y - 4) = (5)/(8)y - (5)/(2)

(d) Switch x and y


y = (5)/(8)x - (5)/(2)

(e) Rename y as the inverse function


g^(-1)(x) = (5)/(8)x - (5)/(2)

(f) Compare with your function


f(x) = (5)/(8)x - (5)/(2)\\\\f(x) = g^(-1)(x)

f(x) and g(x) are inverse functions.

The graphs of inverse functions are reflections of each other across the line y = x.

In the first diagram, the graph of ƒ(x) (blue) is the reflection of g(x) (red) about the line y = x (black)

Question 12

h(x)= x - 2

(a) Rename h(x) as y

y = x - 2

(b) Solve for x:

x = y + 2

(c) Switch x and y

y = x + 2

(e) Rename y as the inverse function

h⁻¹(x) = x + 2

(f) Compare with your function

f(x) = x + 2

f(x) = h⁻¹(x)

h(x) and ƒ(x) are inverse functions.

The graph of h(x) (blue) reflects ƒ(x) (red) across the line y = x (black).

I need help with 11 and 12-example-1
I need help with 11 and 12-example-2
User Wicky
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