Answer:
The probability that an individual sales person earn the bonus by selling more than $2150 in a day is 0.3085.
Explanation:
For a normal distribution N(2000,300), a value of 2150 corresponds to a z-score of
z= (x-μ)/σ = (2150-2000)/300 = 0.5
According to the tables, we have
P(x'>z)=P(x'>0.5)=0.30854
The probability that an individual sales person earn the bonus by selling more than $2150 in a day is 0.3085.