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How many joules of heat energy must be added to 5 grams of liquid water to change its temperature from 10°C to 30°C?

User Diadyne
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1 Answer

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Final answer:

To change the temperature of water, you can use the equation q = mcΔT. In this case, 418.4 Joules of heat energy must be added to 5 grams of liquid water to change its temperature from 10°C to 30°C.

Step-by-step explanation:

To calculate the amount of heat energy required to change the temperature of water, we can use the equation:

q = mcΔT

Where:

  • q is the heat energy
  • m is the mass of the water
  • c is the specific heat capacity of water
  • ΔT is the change in temperature

In this case, we have:

  • m = 5 g
  • c = 4.184 J/(g°C) (specific heat capacity of water)
  • ΔT = 30°C - 10°C = 20°C

Substituting the values into the equation, we get:

q = 5 g × 4.184 J/(g°C) × 20°C = 418.4 J

Therefore, 418.4 Joules of heat energy must be added to 5 grams of liquid water to change its temperature from 10°C to 30°C.

User Lee Warnock
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