148k views
2 votes
Determine whether each statement below is true or false. Justify each answer. a. A linear transformation is a special type of function. A. False. A linear transformation is not a function because it maps one vector x to more than one vector ​T(x​). B. True. A linear transformation is a function from set of real numbers R to set of real numbers R that assigns to each vector x in set of real numbers R a vector ​T(x​) in set of real numbers R. C. False. A linear transformation is not a function because it maps more than one vector x to the same vector ​T(x​). D. True. A linear transformation is a function from set of real numbers R Superscript n to set of real numbers R Superscript m that assigns to each vector x in set of real numbers R Superscript n a vector ​T(x​) in set of real numbers R Superscript m.

User Regisxp
by
5.1k points

1 Answer

7 votes

Answer:

The correct answer is D.

Explanation:

In order to obtain the correct answer we need to recall the definition of function (or map) from one set to another. So, we say that a function (or map) is a way to associate a unique object to every element of a set. In a more mathematical formulation we say that
f:A\rightarrow B is a function if, for every element
a\in A there exists a unique element
f(a)=b\in B.

We need to recall the definition of linear transformation too. So, we say that a map
T: \mathbb{R}^n\rightarrow \mathbb{R}^m is a linear transformation such that


  • T(u+v) = T(u) + T(v), for all
    u,v\in\mathbb{R}^n,

  • T(\alpha u) = \alpha T(u), for every [tex]u\in\mathbb{R}^n and every
    \alpha\in\mathbb{R}.</li></ul><p>Then, from the definition of linear transformations we already know that they are functions. But, in the particular case of linear transformations, we have: &nbsp;</p><ul><li>[tex]A=\mathbb{R}^n and
    B=\mathbb{R}^m,

  • T=f.

Also, a linear transformation must satisfies the conditions stated in its definition.

Just notice that these are the explanation that comes with the option D.

User Arzhh
by
5.6k points