Question

| 2) through: (-5, -4), perp. to y = -x + 2

Answer 1

`y=x+1`

Explanation:

Your generic line will be
`y= mx+q`, so you'll need two condition.

Since it has to be perpendicular to
`y=(-1)x+2`, the product of the slopes needs to be -1, or
`m(-1)=-1`, hence your "generic" becomes
`y=x+q`. Since it has to pass through [/tex](-5;-4), let's put the coordinates in there:
`(-4)=1(-5)+q</p><p>q-5=-4</p><p>q=1`

your line becomes
`y=x+1`