Final Answer:
The initial velocity of the boiling water is 170 meters per second.
Step-by-step explanation:
Identify the relevant equation: We are given the equation H = -16t^2 + 170t, where:
H represents the height of the water at any time t.
The negative coefficient (-16) implies acceleration due to gravity is acting downwards.
The coefficient 170 represents the initial velocity (at t = 0).
Extract the initial velocity: Since the coefficient of the t term (170) represents the initial velocity, the initial velocity is simply 170 meters per second.
Therefore, the initial velocity of the boiling water at the start of its movement is 170 meters per second. This information is directly available from the given equation without further calculations.