Answer:
Explanation:
According to the information given in the statement, there are the following mathematical expressions:
![priceA = K\\priceB = L + Ax](https://img.qammunity.org/2020/formulas/mathematics/high-school/wqp0f8sa1mh7o2k17h3se3d2mbj3uzt8ot.png)
Where
![K,~L~and~A~are~fixed~constants.\\x~is~the~amount~of~driven~mileage.](https://img.qammunity.org/2020/formulas/mathematics/high-school/i3rwqpp9kkpbppjbmvrxom103kos7yyqsi.png)
Considering
![K>L](https://img.qammunity.org/2020/formulas/mathematics/high-school/60jtj5zjm9sqshmq3bgahzzbg424dzwrec.png)
Then
![priceA > priceB\\K > L + Ax\\K - L > Ax\\(K - L)/(A) > x](https://img.qammunity.org/2020/formulas/mathematics/high-school/hoppm3yqec48w1wvwdkchcc4lx5zl0iy7d.png)
The last equation means that to maintain the [text]priceB[\text] lower than [text]priceA[\text], the amount of driven mileage must be less than
. If [tex]x[\tex] becomes greater than the fraction, then the [text]priceA[\text] will be lower than [text]priceB[\text].
[tex]\frac{K - L}{A} < x \\ K - L < Ax \\ K < L + Ax[\tex]