Question

The helicopter in the drawing is moving horizontally to the right at a constant velocity. The weight of the helicopter is W=50900 N. The lift force L generated by the rotating blade makes an angle of 21.0° with respect to the vertical.

(a) What is the magnitude of the lift force?
(b) Determine the magnitude of the air resistance R that opposes the motion.

Answer 1

a.
`L=54521.3 N`

b.
`R=19518.6 N`

Step-by-step explanation:

We are given that

Weight of the helicopter=50900 N

The lift force L generated by the rotating blade makes an angle of 21..0 degree with respect to the vertical.

a.We have to find the magnitude of the lift force.

According to question

`Lcos 21^(\circ)=50900`

`L=(50900)/(cos21^(\circ))=54521.3 N`

b.We have to determine the magnitude of air resistance R that opposes the motion.

R=
`F_x`

`Lsin21^(\circ)=R`

`R=54521.3* 0.358=19518.6 N`