Question

A bottle of water is supposed to have 12 ounces. The bottling company has determined that 98% of bottles have the correct amount. Which of the following describes a binomial experiment that would determine the probability that a case of 36 bottles has all bottles properly filled? n=12, p=36, x=98 n=0, p=0.98, x=36 n=36, p=0.98, x=12 n=36, p=0.98, x=36

Answer 1

n=36, p=0.98, x=36

Explanation:

We are given that The bottling company has determined that 98% of bottles have the correct amount.

So, The probability of bottle having correct amount of water = 0.98

So, p= probability of success = 0.98

So, q = probability of failure = 1-p = 1- 0.98 = 0.02

Now we are given that the probability that a case of 36 bottles has all bottles properly filled

So, n = 36

Now we are supposed to find that all bottles properly filled

So, x must also be 36

Binomial formula :
`P(X=r)=^nC_r p^r q^(n-r)`

`P(X=36)=^(36)C_(36) (0.98)^36 (0.02)^(36-36)`

`P(X=36)=^(36)C_(36) (0.98)^36 (0.02)^(0)`

So, Option D is correct.

n=36, p=0.98, x=36