Answer:
Electric flux in a) , b) and c) is same which is 0.373 × 10 ⁶ N m²/C
Step-by-step explanation:
given,
surface charge (q) = 3.3 × 10⁻⁶ C
to calculate electric flux = ?
a) radius = 0.76 m
area of sphere = 4 π r²
electric flux =
![(q)/(\varepsilon)](https://img.qammunity.org/2020/formulas/physics/high-school/zsl6yx5xlrhnn0d6fd48z35u8zgy2hnf17.png)
![\varepsilon = 8.85 * 10^(-12) C^2/Nm^2](https://img.qammunity.org/2020/formulas/physics/high-school/ksmtr16dij8bw6p889hrq3hrundr90qoxa.png)
electric flux =
![(3.3 * 10^(-6))/(8.85 * 10^(-12) )](https://img.qammunity.org/2020/formulas/physics/high-school/p2i00ximhdxq4gjmgh72xt0mnlf1u7lk6w.png)
flux = 0.373 × 10 ⁶ N m²/C
electric flux in the other two cases will also be same as electric flux is independent of area
so, Electric flux in a) , b) and c) is same which is 0.373 × 10 ⁶ N m²/C