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5 votes
How do i evaluate (7 to the power of 2)to the power of 3)=7 to the power of 5​

User Alan Smith
by
8.3k points

2 Answers

1 vote

[7^(2)]^(3) = 7^(5)

This is not true.

The left side does not equal the right side.

Left side = 7^(6).

Right side = 7^(5).

False statement.

User Warlin
by
8.0k points
3 votes

Explanation:


(7^2)^3=7^5\qquad\bold{FALSE}\\\\\text{because}\\\\7^2=7\cdot7\\\\(7^2)^3=(7\cdot7)^3=(7\cdot7)\cdot(7\cdot7)\cdot(7\cdot7)=\underbrace{7\cdot7\cdot7\cdot7\cdot7\cdot7}_6=7^6\\\\\text{or use}\ (a^n)^m=a^(nm)\\\\(7^2)^3=7^(2\cdot3)=7^6

User BobDickinson
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8.1k points