Question

A container of what volume would be required to store 60.0 moles of a gas at a pressure of 20.0 atm and a temperature of 50.0 Celsius? 12.3 L 79.6 L 8060 L 1250 L

Answer 1

79.6

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Answer 2

The answer to your question is: 79.6 L

Step-by-step explanation:

Data:

n = 60 moles

Pressure = P = 20.0 atm

Temperature = T = 50°C

Volume = V = ?

Convert temperature to Kelvin

°K = 273 + 50

°K = 323

Formula (ideal gas law)

PV = nRT solve for V

V = nRT / P

V = (60)(0.08206)(323) / 20 Substitution

V = 1590.32 /20

V = 79.6 L