Answer:
The factors of
is (x+9) and (x-4)
Solution:
From question, given that
![x^(2) + 5x - 36](https://img.qammunity.org/2020/formulas/mathematics/middle-school/usvro1j76vcbvg39gxezcer2pd9uebldk8.png)
To factorise the above equation, follow the below steps:
![x^(2) + 5x - 36](https://img.qammunity.org/2020/formulas/mathematics/middle-school/usvro1j76vcbvg39gxezcer2pd9uebldk8.png)
5x can be rewritten as 9x – 4x. hence the above equation becomes,
![x^(2) + 5x - 36 = x^(2) + 9x - 4x -36](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tx6z0qzr15dft44tv8aukh1gsujfdx5ud5.png)
Take “x” as common from first two terms and “4” as common from next two terms. Thus the above equation becomes,
= x(x+9)-4(x+9)
Since x+9 is common in both the terms, the above equation becomes,
= (x+9) (x-4)
Thus factors of
are (x+9) and (x-4)