Question

a 45 kg ice skater initially skating at a velocity of 3 m/s speeds up to a velocity of 5 m/s. calculate the difference in the magnitude of momentum of the skater.

Answer 1

Answer: 90m

Explanation:I hope this helps

Answer 2

Answer: 90 kgm/s

Step-by-step explanation:

The momentum (linear momentum)
`p` is given by the following equation:

`p=m.V`

Where:

`m=45 kg` is the mass of the skater

`V` is the velocity

In this situation the skater has two values of momentum:

Initial momentum:
`p_(1)=m.V_(1)`

Final momentum:
`p_(2)=m.V_(2)`

Where:

`V_(1)=3 m/s`

`V_(1)=5 m/s`

So, if we want to calculate the difference in the magnitude of the skater's momentum, we have to write the following equation(assuming the mass of the skater remains constant):

`p=p_(2)-p_(1)=m.V_(2)-m.V_(1)`

`p=m(V_(2)-V_(1))`

`p=45 kg(5 m/s - 3 m/s)`

Finally:

`p=90 kgm/s`