Question

16) Kayla's school is selling tickets to the annual dance competition. On the first day of ticket sales

the school sold 6 adult tickets and 8 child tickets for a total of $98. The school took in $70 on the
second day by selling 2 adult tickets and 8 child tickets. Find the price of an adult ticket and the
price of a child ticket.

Answer 1

The price of an adult ticket is $7 and the price of a child ticket is $7

Explanation:

Let

x -----> the price of an adult ticket

y ----> the price of a child ticket

we know that

First day

`6x+8y=98` -----> equation A

Second day

`2x+8y=70` ----> equation B

Subtract equation B from equation A and solve for x

`6x+8y=98\\2x+8y=70\\---------\\6x-2x=98-70\\4x=28\\x=7`

Find the value of y

`2x+8y=70`

substitute the value of x

`2(7)+8y=70`

`14+8y=70`

`8y=70-14`

`8y=56`

`y=7`

therefore

The price of an adult ticket is $7 and the price of a child ticket is $7