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Write V64 - V-289 as a complex number in the form of a + bi.

A. 8-171
B. 8 + 171
C. 17+ 8i
D.-17-81
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1 Answer

2 votes

Answer:

8-17i

The problem:


√(64)-√(-289)

Explanation:


√(64)=8 because 8 is positive and 8(8)=64.


√(-289)=17i because 17i(17i)=289i^2=289(-1)=-289[/tex]


√(64)-√(-289)


8-17i

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