Question

What is the resistance of five 10Ohm resistors in parellel?

Answer 1

The equivalent resistance is 2 ohms.

Step-by-step explanation:

let the first resistance = R₁ = 10 ohm

let the second resistance = R₂ = 10 ohm

let the third resistance = R₃ = 10 ohm

let the fourth resistance = R₄ = 10 ohm

let the fifth resistance = R₃ = 10 ohm

The equivalent resistance is calculated as;

`(1)/(R_T) = (1)/(R_1) + (1)/(R_2) + (1)/(R_3) + (1)/(R_4) + (1)/(R_5) \\\\(1)/(R_T) = ((R_2R_3R_4R_5)+(R_1R_3R_4R_5)+(R_1R_2R_4R_5) +(R_1R_2R_3R_5)+(R_1R_2R_3R_4))/(R_1R_2R_3R_4R_5) \\\\R_T = (R_1R_2R_3R_4R_5)/((R_2R_3R_4R_5)+(R_1R_3R_4R_5)+(R_1R_2R_4R_5) +(R_1R_2R_3R_5)+(R_1R_2R_3R_4)) \\\\R_T = ((10^5))/((10^4)+(10^4)+(10^4)+(10^4)+(10^4)) \\\\R_T = (10^5)/(5(10^4)) \\\\R_T = (10)/(5) \\\\R_T = 2 \ ohms`

Therefore, the equivalent resistance is 2 ohms.