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What is the 30th term of the linear sequence below?
-4, -1,2,5,8,...

1 Answer

3 votes

Answer:

The 30th term is 83

Explanation:

we know that

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant called the common difference d

in this problem


a_1=-4\\a_2=-1\\a_3=2\\a_4=5\\a_5=8

so


a_2-a_1=-1-(-4)=3\\a_3-a_2=-2-(-1)=3\\a_4-a_3=-5-2=3\\a_5-a_4=-8-5=3

The common difference d is 3

We can write an Arithmetic Sequence as a rule:


a_n=a_1+d(n-1)

Find out the 30th term

we have


n=30\\d=3\\a_1=-4

substitute


a_n=-4+(3)(30-1)


a_n=-4+(3)(29)


a_n=83

User Darren Gansberg
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