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Callie and Madison went to buy concert tickets for themselves and their five friends. The

tickets for the closest section were $45 each, and $30 for each ticket in the other section. They
ended up spending a total of $210. How many tickets of each type did they buy?

1 Answer

2 votes

Answer:

They bought 0 ticket of closest section and 7 tickets of other section

Explanation:

- Callie and Madison went to buy concert tickets for themselves and

their five friends

- That mean they are 7

- Tickets for the closest section were $45 each

- Tickets for other section were $30 each

- They ended up spending a total of $210

- Assume that they buy x tickets for closest section and y tickets for

the other section

∵ They want 7 tickets

x + y = 7 ⇒ (1)

∵ The cost of the closest section ticket was $45

∵ The cost of the other section ticket was $30

∵ They spent $210 on them

∴ 45x + 30y = 210

- All terms have common factor 15, then divide them by 15

3x + 2y = 14 ⇒ (2)

* Now we have a system of equations to solve

- Multiply equation (1) by -2 to eliminate y

-2x - 2y = -14 ⇒ (3)

- Add equations (2) and (3)

x = 0

- substitute the value of x in equation (1) to find y

∴ 0 + y = 7

y = 7

∵ x represents the number of tickets of the closest section and y

represents the number of tickets in the other section

They bought 0 ticket of closest section and 7 tickets of other

section

User Srinivas Ch
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