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Two arcades have different pricing structures. Arcade A costs $5 to enter and $0.60 per game. Arcade B costs $7 to enter and $0.40 per game. How many games do you have to play in order for the two arcades to be the same price?

User Digdog
by
8.2k points

2 Answers

5 votes

Answer:

10 games

Explanation:

Let C be cost and x be number of games

Arcade A: C = 5 + 0.6x

Arcade B: C = 7 + 0.4x

for both arcades to be the same price, Both C's must be equal, hence we equate the right side of both equations:

5 + 0.6x = 7 + 0.4x (subtract 5 fromboth sides)

0.6x = 7 + 0.4x - 5

0.6x = 2 + 0.4x (subtract 0.4x from both sides)

0.6x - 0.4x = 2

0.2x = 2 (divide both sides by 0.2)

x = 2 / (0.2)

x = 10

User Martin GGR
by
6.7k points
5 votes

Answer:

you would have to play 10 games

User Damian Edwards
by
8.1k points
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