Question

The first term of an AP is -1/2 and it's common difference is 4. Find the 9th term

Answer 1

`(63)/(2)`

Explanation:

The n th term of an arithmetic progression is

`a_(n)` = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = -
`(1)/(2)` and d = 4, thus

`a_(9)` = -
`(1)/(2)` + (8 × 4) = -
`(1)/(2)` + 32 =
`(63)/(2)`