Question

What is the equation of the line that is perpendicular to Y= -2/3X+4 and that passes through (-2,-2)?

Y= 3/2x-10/3
Y=3/3x-5
Y=3/2x+1
Y=3/2x-2/3​

Answer 1

y=3/2x+1

Explanation:

You’re trying to find the perpendicular like equation of y=-2/3x+4 that passes through (-2,-2). Use reciprocal of slope -2/3= 3/2. use y=mx+b and plug in info, (-2,-2) will be plugged in for both y and x and 3/2 will be plugged in for m making -2=(3/2)(-2)+b. Multiply the () to get -2=-3+b, add 3 to both sides of the equation to get 1=b. Use your info to make the finished equation y=3/2x+1

Answer 2

`y = (3)/(2)x + 1`

Explanation:

-2 = 1½[-2] + b

-3

1 = b

y = 1½x + 1

** 1½ = 3⁄2

Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE RATE OF CHANGES [SLOPES]:

-⅔ → 1½

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