Question

10. A bullet is moving at a speed of 367 m/s when it embeds into a lump of moist

clay. The bullet penetrates a foe and comes to a stop at a distance of 0.0621m.
Determine the acceleration of the bullet while moving into the clay.

Answer 1

1080000 m/s2

Step-by-step explanation:

Answer 2

-1.08×10⁶ m/s²

Step-by-step explanation:

Given:

v₀ = 367 m/s

v = 0 m/s

Δx = 0.0621 m

Find: a

v² = v₀² + 2a (x − x₀)

(0 m/s)² = (367 m/s)² + 2a (0.0621 m)

a = -1.08×10⁶ m/s²