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Evaluate M^2 /p^2 for M = 10, N =-5p and P = -2

User Petero
by
6.4k points

1 Answer

3 votes

Answer:

The solution of
\bold{(M^(2))/(P^(2))} for M = 10, N = -5P and P = -2 is 25

Solution:

From question, given that the value of M is 10 and N is -5p and P is -2

We have to evaluate the value of
(M^(2))/(P^(2)),

By substituting the values of M and N, we get


(M^(2))/(P^(2)) = (10^(2))/((-2)^(2))

Expanding
\bold{10^(2)}:

Here 10 is the base value and 2 is the exponent value. So the base term 10 is multiplied by itself two times.


10^(2) = 10 * 10 = 100

Similarly expanding
\bold{(-2)^(2)}:

Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.


(-2)^(2) = -2 * -2 = 4

So the equation
(M^(2))/(P^(2)) = (10^(2))/((-2)^(2)) becomes,


(M^(2))/(P^(2)) = (100)/(4)

By dividing 100 by 4 , we get the result as 25

Hence the solution of
\bold{(M^(2))/(P^(2))} when M = 10 and P = -2 is 25

User Pallab
by
7.4k points
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