Question

What is the slope-intercept form of the following equation? 10x + 4y = 16 options: a.) y =−5/2x + 16 b.) y = −5/2x + 4 c.) 4y =−10x + 16 d.) y = −10x + 16

Answer 1

`y=-(5)/(2)x+4`

Explanation:

we know that

The equation of the line in slope intercept form is equal to

`y=mx+b`

where

m is the slope

b is the y-intercept

we have

`10x+4y=16`

Solve for y

That means -----> isolate the variable y

Subtract 10x both sides

`4y=16-10x`

Divide by 4 both sides

`y=(16-10x)/4`

Simplify

`y=4-(5)/(2)x`

Rewrite

`y=-(5)/(2)x+4`

Answer 2

The answer is option (b), y=-5/2x+4

Explanation:

The slope intercept form is a way of expressing the equation of a straight line; where there are two variables that vary in a linear form. The equation is always of the form; y=mx+c

Where;

• y and x represents the variables on the y and x axis respectively
• m is a real number representing the slope
• c is also a real number representing the y-co-ordinate, where the line intercepts the y-axis

Solving for y in 10x+4y=16

(4y)/4=(-10x)/4+(16/4)

The answer is y=-5/2x+4, option (b)