Question

What is the area of a figure that is formed using a parallelogram with base 5.2 meters and height 3 meters, and a semicircle with a radius of 4 meters. Round to the nearest tenth, if necessary.

Question 1 options:

40.7 m2

40.733 m2

33.3 m2

28.2 m2

Answer 1

40.7m^2

Explanation:

Base×Height= 5.2m×3=15.6m2

Area of semicircle= Pie r^2= Pie×4^2=16×pie

pie×16÷2=8×pie

8×3.14=25.12m2

15.6m2+25.12m2=40.72m2

rounded to nearest tenth=40.7m2

Answer 2

Answer:
`40.7\ m^2`

Explanation:

Given : A parallelogram has base 5.2 meters and height 3 meters, and a semicircle with a radius of 4 meters.

Area of parallelogram is given by :-

`A_p=b* h` , where b is base and h is height of parallelogram.

`=5.2*3=15.6\ m^2` (1)

Area of semicircle :-

`A_s=(\pi r^2)/(2)`, where r is radius.

`=(3.14*4^2)/(2)=25.12` (2)

Now from (1) and (2),. the area of the combined figure will be :-

`A=A_p+A_s\\\\=15.6+25.12=40.72\approx40.7\ m^2`