Question

On a coordinate plane, a piecewise function has 2 lines. The first line has a closed circle at (negative 4, negative 4) and goes up to an open circle at (negative 1, 2). The second line has a closed circle at (negative 1, 3), continues horizontally to (1, 3), and then goes down to a closed circle at (4, 0).

What is the value of h(3)?

–2
–1
1
2

Answer 1

c edge2020

Explanation:

Answer 2

1

Explanation:

The last part of the line starts from (1,3) and goes to (4,0)

We have two points, so we figure out the equation of this line with the formula:

y = mx + b, where m is the slope and b is the y intercept

m =
`(y_2-y_1)/(x_2-x_1)`

m =
`(0-3)/(4-1)=(-3)/(3)=-1`

So we can now write y = -x + b

Plugging in a point (1,3), we get:

3 = -1 + b

b = 3+1 = 4

The equation is y = -x + 4

To find h(3), we substitute 3 into x and find the value of y:

y = -x + 4

y = -3 + 4

y = 1

Thus, h(3) = 1