Question

Our Sun emits most of its radiation at a wavelength of 550nm. If a star were 5.00 times hotter than our Sun, it would emit most of its radiation at a wavelength of nm 1st attempt Feedback Q See Hint Our Sun emits most of its radiation at a wavelength of 550 nm. If a star were 5.00 times hotter than our Sun, it would emit most of its radiation at a wavelength of 275 nm

Answer 1

`\lambda_(star) = 1.100* 10^(-7) meter`

Step-by-step explanation:

By wein's law

`\lambda* T= 2.898* 10^(-3) kelvin meter`

where;

λ = wavelenght

T= Temperature (in kelvin)

`2.898* 10^(-3) mk` = Wein's constant

so

`\lambda*  T(sun) = 2.898* 10^(-3)`

`550* 10^(-9)* T (sun) = 2.898* 10^(-3)`

`T (sun) = (2.898* 10^(-3))/( 550* 10 ^(-9))`

T (sun) = 5269.09 kelvin

from data given we have

`T( star ) = 5* T (sun)`

so,

`\lambda_(star)*  T(star) = 2.898* 10^(-3)`

`\lambda_(star)* 5* T(sun) = 2.898* 10^(-3)kelvin meter`

`\lambda_(star)* 5* 5269.09 = 2.898* 10^(-3)kelvin meter`

`\lambda_(star) = ((2.898* 10^(-3)kelvin meter))/((5 * 5.269 * 10^(3)kelvin))`

`\lambda_(star) = 1.100* 10^(-7) meter`